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Report, edit, etc...Posted by Staredit.Net Essence on 2005-12-10 at 03:58:35

Here is a math equasion I was given before I was going to bed. It is from my friend off of PalTalk, who recieved it from another person in his room:

QUOTE(jesteraclown)

okay.. ready.. the sum of all points is equal to 1/2 N times (N+1) where N equals the highest whole number in the counting series.. so, 1+2+3+4=10; thus 1/2 of 4 X (4+1)=10. This is an easy means for calculating points alike the sum of one thru one trillion; 1/2 one trillion times one trillion plus one..

Hmmm.. Let me write it out:

½ of N•(N+1) = X

Now, written out with the example he used (1+2+3+4=10)

½ of 4•(4+1) = 10

Now doing this, following simple math rules, in my eyes, it will not (I said not before Demaris pointed out that I screwed up with the operations) work:

½ of 20 = 10

EDIT: Yeah. It's plausible. Fixed up my errors, too.

Report, edit, etc...Posted by Demaris on 2005-12-10 at 04:31:12

QUOTE(Kellimoose @ Dec 10 2005, 03:58 AM)

Here is a math equasion I was given before I was going to bed. It is from my friend off of PalTalk, who recieved it from another person in his room:

QUOTE(jesteraclown)

Hmmm.. Let me write it out:

½ of N•(N+1) = X

Now, written out with the example he used (1+2+3+4=10)

½ of 4•(4+1) = 10

Now doing this, following simple math rules, in my eyes, it will not work:

½ of 17 = 10

Simplified: Don't ask me. I'm stumped because I always forget the rules with multiplying and dividing fractions. But to me, whatever the answer is on the side of the 17, it will != (Little present for you programmers

) 10

Anyways...

I'm asking you guys if this is a plausible equation, since the highest I got was into Algebra 1B
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You messed up the order of operations.

1/2 of 4(4+1)
1/2 of 4(5)
1/2 of 20 = 10.

Makes sense if you know some math

Report, edit, etc...Posted by Staredit.Net Essence on 2005-12-10 at 05:03:26

shiz. You're right *Smacks head* I forgot that you have to do things in the () before...

Okay. I'm closing this now.

Report, edit, etc...Posted by DT_Battlekruser on 2005-12-10 at 17:17:10

You can prove it by mathematical induction.

Hypothesis: 1+2+3......+n = n(n+1)/2

Prove true for n=1

1 = 1(1+1)/2?
1 = 2/2?
1 = 1

Assume true for k.
1+2+3....+k = k(k+1)/2

Prove true for k+1
1+2+3.....+k+(k+1) = (k+1)(k+2)/2?
(k(k+1)/2)+(k+1) = (k+1)(k+2)/2?
((k[sup]2[/sup]+k)/2)+(k+1) =(k+1)(k+2)/2?
((k[sup]2[/sup]+k)/2)+((2k+2)/2) = (k+1)(k+2)/2?
((k[sup]2[/sup]+3k+2)/2) = (k+1)(k+2)/2?
(k+1)(k+2)/2 = (k+1)(k+2)/2

Therefore, 1+2+3...+n = n(n+1)/2

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