Report, edit, etc...Posted by Staredit.Net Essence on 2005-01-07 at 15:43:32
can anyone help me with a problem? it annoys me, it goes 123-4-5-6-7+8-9= 100, you have to figure out another way to get 100 in consecutive order, closest i got is 101 and 99 :/ plz help if you can 
Report, edit, etc...Posted by Kow on 2005-01-07 at 17:40:52
18+19+20+21+22
Report, edit, etc...Posted by LegacyWeapon on 2005-01-07 at 18:02:31
I think he means with 123456789 = 100
Report, edit, etc...Posted by Kow on 2005-01-07 at 18:04:07
QUOTE(cHaOz^ @ Jan 7 2005, 03:43 PM)
consecutive order
Im just following directions...
Report, edit, etc...Posted by LegacyWeapon on 2005-01-07 at 18:09:24
Then there are infinite possibilities. Use the forumula:
x = First Number in the Sequence
x+1 = Second number in the Sequence
x+2 = Third number in the Sequence
x+n = Last number in the Sequence
(x)+(x+1)+(x+2)+...+(x+n)=100
Solve.
The groupings aren't required. They just help to see where I put the terms x and x+1.
He didn't even specify integers. Why not use rational numbers!
x = First Number in the Sequence
x+1 = Second number in the Sequence
x+2 = Third number in the Sequence
x+n = Last number in the Sequence
(x)+(x+1)+(x+2)+...+(x+n)=100
Solve.
The groupings aren't required. They just help to see where I put the terms x and x+1.
He didn't even specify integers. Why not use rational numbers!
Report, edit, etc...Posted by Staredit.Net Essence on 2005-01-07 at 18:59:51
sry, you can only use add, times, divide, and subtract, and the order of numbres has to 123-4-5-6-7-8-9