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Example, when I place a beacon at location X, then I place two more beacons at location Y and N. In game, when I move a unit on beacon X, how can I make it so it teleport randomly to either beacon Y and N? If you know please tell me how its done, if its not possible, please also tell me. Thanks

Randomize a switch before the teleport. Then when the teleport occurs, move to either point Y if the switch is set, or N if it's cleared. Re-randomize the switch during each teleport.

Sorry to ask, but can you make something like the chart to show me how to do this?

Condition
1-Bring to Location X.

Action
1-Randomise Switch 1 (which has 2 outcomes, set and clear - and it doesn't matter whether the current status is set or clear)
-Preserve trigger.

Condition
1outcome 1- Player Z brings at least 1 any unit to location X (I did this extra bring condition to let starcraft execute the trigger only when units are brought to the location because all switches start off as 'clear')
-Switch 1 is clear.

Action
1outcome 1- move 1 anyunit at Location X to Location Y.
-Preserve trigger.

Condition
1outcome 2- Player Z brings at least 1 any unit to location X.
-Switch 2 is clear.

Action
1outcome 2- move 1 anyunit at Location X to Location N.
-Preserve trigger.


Those are the triggers for 'bring' to beacon X.

Do them respectively for X and N


As for the chart u requested, these are the combinations.
-Bring to location X (randomise switch 1)
-Switch 1 clear = move to Loc. Y
-Switch 1 clear = move to Loc. N

-Bring to location Y (randomise switch 2)
-Switch 1 clear = move to Loc. N
-Switch 1 clear = move to Loc. X

-Bring to location N (randomise switch 3)
-Switch 1 clear = move to Loc. X
-Switch 1 clear = move to Loc. Y


These are the default triggers... however use a switch or something to prevent continous instant moving of units. (or just make the 'move to' locations different. L = e.g. Move to location Xa instead of location X)

Not proof read.

What if there were more then 3 beacons?

Would the 4th beacon be like this:
Condition:
- Player 1 brings at least 1 men to 'X'
- 'Switch 3' is cleared.
Action:
- Move all men for Player 1 at 'X' to 'C'
- Preserve Trigger

Would the 5th beacon be like this:
Condition:
- Player 1 brings at least 1 men to 'X'
- 'Switch 4' is cleared.
Action:
- Move all men for Player 1 at 'X' to 'Z'
- Preserve Trigger

And if I wanted to make the the beacon 'C' teleport randomly too, would it look like this:

Condition:
- Player 1 brings a least 1 men to 'C'
Action:
- Randomize 'Switch 2'.
-Preserve Trigger

Condition:
- Player 1 brings at least 1 men to 'C'
- 'Switch 1' is cleared.
Action:
- Move all men for Player 1 at 'C' to 'X'
- Preserve Trigger

Condition:
- Player 1 brings at least 1 men to 'C'
- 'Switch 2' is cleared.
Action:
- Move all men for Player 1 at 'C' to 'Y'
- Preserve Trigger

Condition:
- Player 1 brings at least 1 men to 'C'
- 'Switch 3 is cleared.
Action:
- Move all men for Player 1 at 'C' to 'N'
- Preserve Trigger

Continue.... ??
Sorry im all confuse about the switches thing.

No the idea behind randomizing switches is that you take a couple of switches and randomize them. Each switch has two possibilities, on or off. So one randomized switch can give two outcomes on or off. Two switches randomized can give on and on, off and off, on and off, and off and on.
0= on 1= off
1 switch
0
1

2 switches
00
11
10
01

Now to use this in a situation you want a randomize you would give each situation its own possibility of switch outcomes. So say you want to randomize 3 things. You would need 2 randomized switches which give 4 possibilities. You give each thing its own possibility. But now you are left with the fourth possibility, with this you must "rerandomize" the switches.

Example: three events you want randomized

event 1
event 2
event 3

2 switches = 4 outcomes
00
11
10
01

so then you give each event an outcome of switch settings as the condition

event 1 = 00
event 2 = 11
event 3 = 10
Rerandomize = 01

therefore when you randomize the 2 switches they can be in either 00,11,01,or 10 state.

If you have 4 events you can just give the fourth event the 01 possibility

If you want 5 now, then you must use 3 switches, which gives you, 8 outcomes
000 = event 1
001 = event 2
010 = event 3
011 = event 4
100 = event 5
101 = rerandomize
110 = rerandomize
111 = rerandomize

As you increase the number of events you must use more switches because you need more switch setting possibilities.
The number of possibilities is 2 ^ number of switches
so with four switches you can get 16 different possibilities

Heres the randomization tutorial http://www.staredit.net/index.php?act=tuto...e=Randomization

Ok a summary of what I said before all combined

player 1 steps on beacon

Conditions:
Current player brings 1 unit to location "beacon"
switch "onbeacon" clear
switch "teleport" clear

Actions:
move location "check" on current player
set switch "onbeacon"
set switch "moveunit"
Randomize switches
preservetrigger



Trigger results of randomize
Conditions:
switch 1 set
switch 2 set
switch on beacon set
switch "moveunit" set

Actions:
move unit to "another location"
set switch "teleport"
clear switch "moveunit"
move location "teleport" on unit



Trigger for if player lands on same beacon

Condition:
switch "teleport" set
current player brings 1 unit to location "check"
Action:
move location "check" on unit
set switch "moveunit"
randomize switches
preservetrigger

Trigger for if player lands on diff beacon

Condition:
switch "teleport" set
current player brings 0 unit to location "check"
Action:
clear switch "teleport"
preservetrigger




Trig to clear switch "onbeacon" once player moves off beacons to stop teleporting

Condition:
Currentplayer brings 0 units to location "teleport"

Action:
Clear switch "onbeacon"
preservetrigger


Also if you are going to use an absurd number of teleport spots, and dont want to use as many locations, 1 per teleport, theres a way to do it, but it will probably take more trigs


Made a map to test my trigs and as an example

This switch system is more complicated then I thought.
After looking through your map in StarEdit, I still don't know what to do.

I know a very easy system of random ?I just don't know how to explaine it....
But its involes a units patroling and the unit goes on loaction which active the random.....

Well I Know An Easier Way Its create that unit anywhere at any location

Or This


Description: Warp

Player:You Choose

Condition: Always Or You Choose

Action: Create Marine Anywhere

To Make It Look Better You Can Try Using Arbiter Warp It looks like its teleported but its not get it?

What does that solve?

Besides proving that his skill level should be set "beginner", or he is spaming? Not much.

Hmm, I am not sure if your skill level really is average. Anyways...

Make the following triggers if you have 6 becons:

Trigger

Description:

Randomize switches...

Players:

¤ what ever player you want

Conditions:

¤ always

Actions:

¤ randomize switch 1

¤ randomize switch 2

¤ randomize switch 3

¤ preserve trigger

Trigger

Description:

Teleport what ever unit you want to becon "b"

Conditions:

¤ switch 1 is cleared

¤ switch 2 is cleared

¤ switch 3 is cleared

Actions:

¤ teleport all units you want at becon send units to becon "b"

¤ preserve trigger (if you want)

Trigger

Description:

Teleport what ever unit you want to becon "c"

Conditions:

¤ switch 1 is set

¤ switch 2 is cleared

¤ switch 3 is cleared

Actions:

¤ teleport all units you want at becon send units to becon "c"

¤ preserve trigger (if you want)

Trigger

Description:

Teleport what ever unit you want to becon "d"

Conditions:

¤ switch 1 is set

¤ switch 2 is set

¤ switch 3 is cleared

Actions:

¤ teleport all units you want at becon send units to becon "d"

¤ preserve trigger (if you want)

Trigger

Description:

Teleport what ever unit you want to becon "e"

Conditions:

¤ switch 1 is set

¤ switch 2 is set

¤ switch 3 is set

Actions:

¤ teleport all units you want at becon send units to becon "e"

¤ preserve trigger (if you want)

Trigger

Description:

Teleport what ever unit you want to becon "f"

Conditions:

¤ switch 1 is cleared

¤ switch 2 is set

¤ switch 3 is set

Actions:

¤ teleport all units you want at becon send units to becon "f"

¤ preserve trigger (if you want)

Trigger

Description:

Teleport what ever unit you want to becon "g"

Conditions:

¤ switch 1 is cleared

¤ switch 2 is cleared

¤ switch 3 is set

Actions:

¤ teleport all units you want at becon send units to becon "g"

¤ preserve trigger (if you want)

Wow.... you guys aren't helping him by throwing a whole bunch of triggers in his face... you can always show the way to do it, but teaching it to him is alot better.



Well, firstly random is alot easier then you'd think.
There are 2 common ways to do this,


1) Unit patrol
2) Switch Randomize



1) Unit Patrol
-Ever type "black sheep wall" on a map you were playing one day, and you saw a marine running around back and forth at the bottom? Well, this was either their custom timer, or randomized patrol trigger.


What does it do?
-The Unit patrol is basicly a unit patrolling between 2 locations, and two triggers detecting weither the unit is there or not.

How do you make em?
-Simple. It only refers to your conditions to your trigger.
-Create two 2x2(or bigger) locations one is labeled "1" one is labeled "2" at an area where players cannot see right next to each other and place a marine for a computer player, lets say its player 8, within location "1". and then in a trigger issue an order ONLY ONE TIME for it to patrol to location "2". now, you have your random. Now, create two triggers:

=Player 1
*Conditions:
-player 8 brings 1 marine to "1"
-player 1 brings 1 unit to "x"

+Actions:
-move unit at "x" to "y"
-preserve.
_Comment:Possibility 1




this is for the first possible scenario.


=Player 1
*Conditions:
-player 8 brings 1 marine to "2"
-player 1 brings 1 unit to "x"

+Actions:
-move unit at "x" to "n"
-preserve.
_Comment:Possibility 2



this is for the second possible scenario.


Now, we must understand why this is working... well, this is randomized because the marine is moving from "1" to "2" constantly and the players don't know when it moves around, and because they don't know when the marine is in each location, they bring the unit being transported to "x" allowing for one of the two possibilities to occur. We must tie in the two locations:

"1" is tied with "y"
"2" is tied with "n"

What do I mean by "tied with"?
Means that the locations corospond to each other.


If the marine is at "1", then the trigger will move it to "y"
And if the marine is at location "2" then the trigger will move it to "n".

and these one of these two situations are executed when the player brings a unit to "x".


When dealing with randomized triggers, think of it as simply ONE trigger. Because there can only be ONE outcome per time the random is executed. Especially with 2 randomized situations.


The downside with this random is that if a player uses a "map hack" or predict when the marine moves, then they could break the randomness..


you wanted a chart?


"when marine is at "1"=x to "y"\__ when player brings to "x"___
"when marine is at "2"="x" to "n"/



and 2) Switch Randomize
has already been described..






Edit: yes you're right chu... =X

He doens't need more people posting triggers or explainations of randomization. He needs to go back and read every post and tutorial on this site related to it again and again until he understands it. Because you've all broken it down to a very simple explaination that anyone can understand.

My way lets you go to any beacon and you can go to any beacon and it will teleport you, it also does it only once when you step on a beacon, and doesnt reset until you move off of it so there is no constant teleporting, and it checks to see if you teleport to a different beacon and if not then it teleports again.

Hehe, it was so simple to say it in my first post. Guess I'm really taking for granted that people just don't know this stuff. But then again, there are 3 abstract concepts involved here, which can easily be baffling to anyone who doesn't know them already: Trigger execution ordering (randomize, teleport, then re-randomize), switch binary (basic binary numbers), and randomized binary switches.

Its best to go step by step and explain the meanings behind EVERYTHING

devilisk, if I explained the meaning of everything I try to describe... which I sometimes do (and we all know how long people's attention spans last on those), it sometimes does LESS to get the point across than packaging it into a sentence or two. Most of the time, people can figure out what they need to do from a simple set of instructions better than they can from pages and pages of details. All it takes is some brain work and abstract ability... two things unfortunately lacking in today's population.

If you don't already know the concepts though, then the only way to get them is through exposure and patience, which no single forum post can instill. As soon as the basics sink in though, the rest of the details and steps follow suit easily.

well for randomization its pretty simple, you randomize switches and you use each possible outcome with each switch having two settings

the thing is before you can explain anything with randomization you must make sure they know all about randomization and understand the ideas behind it

I tried my best to understand every post you guys make because my English isn't that well. Um, and here's a map I tried making the teleports... I tested it in game, doesn't work... any of you know what I did wrong?

Nonono. A switch can be set or cleared. When you randomize it, you get a random result between set and clear. It's like flipping a coin, where heads could be cleared and tails could be set. When you flip 3 coinds (randomize 3 switches) they land and give you a random result. The same happens when you randomize switches in SC. So your triggers dont work because they set the switches after they are randomized, and the trigger with all 3 switches set goes off and sets them again.

Let me post a working version of your test map.

ADDITION:
[attachmentid=4205]

ADDITION:
This is how it works ... You have 3 switches, which means you can create 8 possible actions with them. And you have 1 more switch which controls the action, it makes it so that it happens only once. When you bring the unit to the location, it randomizes the 3 switches, and sets the activator switch so that an action is made. When the activator switch is set, it compares all your switch combinations with the first 3. When it lands on any of the first 6 combinations (assigned to the 6 teleport locations) then it teleports the unit to the location assigned to the combo and then clears the activator so you can move the unit again.

Are you talking to Bolt?

bah my way you can teleport from going onto any beacon

I'm just providing a simple enough to understand example for him. He can grasp other concepts later.

deadmarine, do you know what "Binary" numbers are? If you don't, it goes like this:

____8_4_2_1 (The _ are spaces so I can keep the numbers in line.)
____0_0_0_0

Ok heres how "binary" (word used for this type of math) works. The numbers above represent "powers" of 2 since in English "bi-" = two ("bi-"cycle = 2 cycles, or 2 wheels) [color=yellow] Now for the concept: as stated in earlier posts for the bottom row, 0 = off, and 1 = on.

____8__4__2__1
____0__0__0__1
By putting this 1, or "on" sign under the number 1, the number that comes out is 1.

____8__4__2__1
____0__0__1__0 Now since the 1 or "on" sign is under the number 2, the number that comes out is 2. Simple yes? Now here comes a slightly more difficult part.

____8__4__2__1
____0__0__1__1
Now there are two 1/on signs under the numbers. That means you add the numbers that are "on" together. Since the 1/on is under the numbers 2 and 1, it is 2+1, or 3.
To understand why it is powers of two are used (2^0 = 1, 2^1 = 2, 2^2 [or 2•2] = 4, 2^3 [or 2•2•2] = 8, and so on) but not powers of 3 or any other number, is because of how weird the number 2 is. With the 'binary' system, you can get an "output" of all whole numbers.
____8__4__2__1 (This shall be the top row or top of the graph)
____0__0__0__0 = 0
____0__0__0__1 = 1
____0__0__1__0 = 2
____0__0__1__1 = 2+1, or 3
____0__1__0__0 = 4
____0__1__0__1 = 4+1, or 5
____0__1__1__0 = 4+2, or 6
____0__1__1__1 = 4+2+1, or 4+3, or 7
____1__0__0__0 = 8
This pattern (if you can see it) goes on and on exponentially on the top column (x•x•x•x•x•x•x•x and so on) 1, 2, 4, 8, 16, 32, 64, 128, 256, 512 and so forth.

Now if you already understand this, you just don't know how to put it into trigger form. Look at switches: they only have an "on" position, or an "off" position. They start off at the "off" position in the game if you did not know.

Isn't it interesting that 'binary' numbers also have an "on" position (1) and an "off" position (0)? Why not say the numbers on that 'binary' chart up there, instead of 8, 4, 2, and 1, make them s4,s3,s2,s1 (switch 4, switch 3, switch 2, switch 1)??? They can be substituted with each other because they BOTH act EXACTLY THE SAME! They both have an "on" switch and an "off" switch, and depending on which ones are "on" and "off"(condition for a trigger), they will produce a different number, or actions for a trigger.

Do you see how they are alike deadmarine? I hope you do, because this is what they were talking about in posts before about "0" and "1".

The Trigger
The triggers for anything you want to happen in a game are easy or hard depending upon what you know and also your logic and thinking skills. Now, you want when some guy goes to this BLUE beacon (Colors are cooler things to look at than variables like x, y, and other things), he will either teleport to the TEAL beacon, the RED beacon, or the PURPLE beacon. Ok, now that we see what we're trying to do we have to put it into trigger form.

In triggering, you would put 1 location over each beacon and do the triggers with the laoctions, but since I do not want to confuse you, I shall say that the beacons already have locations on them.

Knowing about how switches work exactly like this foreign 'binary' system, lets try to find the least amount of switches we need to do this: To figure out how many switches we need, we use the numbers back from the old 'binary' system (since S1=1,S2=2,S3=4,S4=8 and so on) and work the graph below.

___S4__S3__S2__S1
____0___0___0___0 = 0
Since there are 3 possible beacons to teleport to, we're going to need more than 0 switches.
____0___0___0___1 = 2
Nope, 1 switch only works when you have two choices, not three. To understand these two "choices", think of a coin. When you flip a coin, it is either heads or tails. You could make heads = 0 and tails = 1, making 2 choices. When Switch 1(S1) is cleared (0) it would be "heads". When Switch 1 is set (1) it would be "tails".
____0___0___1___1 = 4
The maximum amount of choices TWO switches can handle is 4. Therefore, you need two switches to teleport to either the TEAL, PURPLE, or RED beacon randomly from the BLUE beacon. Any of this making sense to you?

Now since each number that comes out of this 'binary' system, we could substitute the numbers to be the actions of the trigger. Some people have tried to show you how the triggers would look like, but you couldn't understand. I think you'll be able to understand mine hopefully. Watch:

Trigger

Description:

Putting binary numbers into this trigger

Players:

¤ Player Kirby

Conditions:

¤ S2 = 0 (cleared)

¤ S1 = 0 (cleared)

Actions:

¤ 0

Understand? "0" can be any action that you wish it to be. And by the beauty of this 'binary' system, you will always get a different number, or "separate action".

Trigger

Description:

Continuation for Binary numbers

Players:

¤ Player Kirby

Conditions:

¤ S2 = 0 (cleared)

¤ S1 = 1 (set)

Actions:

¤ 1

Don't become "shocked" if you can't understand the trigger. This is exactly like the 'binary' system I had shown you at the beginning of this writing. I will add 2 more triggers onto this text just to show you that there ARE 4 possibilities for two switches.

Trigger

Description:

More Binary numbers

Players:

¤ Player Kirby

Conditions:

¤ S2 = 1 (set)

¤ S1 = 0 (cleared)

Actions:

¤ 2

Trigger

Description:

Binary numbers, yet again

Players:

¤ Player Kirby

Conditions:

¤ S2 = 1 (set)

¤ S1 = 1 (set)

Actions:

¤ 2+1, or 3

So the possibilites are: 0, 1, 2, 3. That is 4 possibilities. Now, since there are only three beacons, what do we do with the 4th possibility? Let us look at how randomizing switches work.

'Randomizing' a switch means when you put this as an action in a trigger, the switch will turn null (neither cleared nor set) and then become either cleared or set. You can only 'randomize' one switch at a time, or that to 'randomize' two switches you have to put two actions in a trigger, one for each switch. I am now going to use about the same method one person used to show you how this works, but with the knowledge you have just learned you should be able to understand.

Ok, lets say that when the outcome we get after 'randomizing' the switches equals 0, the player will teleport to the TEAL beacon. In other words, when the person is on the BLUE beacon, if S2 = 0 and S1 = 0, then the outcome will be 0 and the person will teleport to the TEAL beacon. Simple to understand now, isn't it?

Now lets say that you are teleported to the PURPLE beacon when the outcome is 1 and the RED beacon when the outcome is 2. For switch terms, you would teleport to the purple beacon when S2 = 0 (Cleared) and S1 = 1 (Set); you would also teleport to the red beacon when S2 = 1 (Set) and S1 = 0 (Cleared).

I hope you get what I am saying. But wait, what if this 'randomizing' makes the outcome be 3 ??? Since we want it to be an equal chance of going to each of the three colored beacons, how can we do it if there are FOUR possibilities???

Have you ever heard of a game in real life called "Four Corners"? It goes like this: one person stands in the center of a square room blindfolded and counts to 10. While the person is counting, all the other people walk around the room. By the time the person blindfolded gets to 10, the people NEED to be at one of the four corners of the room, or else they are out (they lose ). Now this blindfolded person makes a random guess by pointing at one of the four corners of the room. If the person points at a corner with people in it, the people in the corner LOSE! The game repeats until there is one winner and bla bla bla

Now heres the thing about this game: not all of the corners need to have a person there. So lets say all of the people trying to not lose stay in 3 of the 4 corners. What happens when the blindfolded person points to a corner that has no people in it? The game just repeats; its as simple as that. If you don't understand, think of it this way.

You are the person with the blindfold. There are 3 people still left in the game: Mr. Blue, Ms. Teal, and Mr. Purple. Since all of them want to be the last one left, they all make sure they're each in separate corners just in case if you pick two of them out at the same time, leaving the 3rd one left the winner. So now, you have counted to 10, and there are 3 corners, each filled with one person/outcome. You pick the empty corner. What happens? You do the round over!
THAT IS WHAT OUR 4TH POSSIBILTY DOES; IT WILL JUST RE-DO THE GUESS!

Now we have just gotten done with the extremely long and boring (but needed!) explanation of what the trigger will do. Unfortunately, now we have to do the literal terms. What I mean is that in math, you are solving how many cans paint you need to buy to paint a room. Lets say you need 4.6574 cans of paint to color your bathroom/watercloset. Even though techincally you need 4.6574 cans of paint, there aren't many stores out that that sell about 2/3's of a can of paint. It's like being paid 1/2 a penny for doing a job. In reality, Either you get paid nothing, or 1 penny. So, you need to buy 5 cans of paint, even though you only need 4.6574 "cans". I hope you already learned that in math because that is the best I can explain that concept.

The Real Triggering
<(o.o)> If you are tired, take a 2 to 5 minute rest. This has gotten rediculously long, so you should try to understand everything slowly enough that you don't get overwhelmed(completely confused).

Back to the literal terms of how triggers work. Now to make things easy, lets name the "location" over the Blue beacon BLUE, the teal beacon TEAL, the purple beacon PURPLE, and the red beacon RED. Easy to remember right? The Blue beacon is the beacon we're going upon, and the other 3 beacons are where we are teleporting to from the blue beacon, okie-dokie?

Trigger

Description:

Randomizing the switches

Players:

¤ Player Kirby

Conditions:

¤ I have gone to the blue beacon, which is at location BLUE

Actions:

¤ Make S2 Random

¤ Make S1 Random

¤ Set the Control Switch

¤ Preserve trigger (to use this more than once)

I believe you understand the condition, and that you also understand S2 has 'randomly' become cleared (0) or set (1) and that S1 has now also become 'randomly' cleared (0) or set (1). I don't know if you understand the control switch though. The control switch is like a fuse box. It is a fail-safe to make sure that the teleport to the beacons will truly be random. I will show you only one possibility for the teleports and how the mysterious 4th possibility (Re-Do the 'randomizing') works.

Trigger

Description:

Whats with the Control Switch?

Players:

¤ Player Kirby

Conditions:

¤ S2 = 1 (Set)

¤ S1 = 0 (Cleared)

¤ The Control Switch is set.

Actions:

¤ 2, or I will be teleported to the red beacon, which is at location RED

¤ Clear the Control Switch.

¤ Preserve trigger. (to use it more than once.)

Remember that Teal = 0, Purple = 1, and Red = 2. Now to explain why you have this control switch. The reason is that lets say you have 2 units that want to teleport alright? You have them teleport one at a time.
Let us say that when the first unit came to the blue beacon, or location BLUE, the switches 'randomized' making S2 become 1 and S1 become 0. That means the number outcome is 2 (because S2 is actually 2 and S1 is actually 1 on the chart far above), so therefore the unit will teleport to the red beacon, correct?
__4__2__1_
__0__1__0_ = 2

_S3_S2_S1_
__0__1__0__ = 2 (Just for recap of beginning)

Without that Control switch in place, as soon as that 2nd unit steps on that blue beacon he will teleport to the red beacon because the 2nd trigger (Whats with the control switch) will happen before the 1st trigger (Randomizing the switches) can do its duty. THAT is why you need the control switch. No matter whether the switches are set or cleared when the unit steps on the beacon, the switches will 'randomize' a split second before the control switch is set, making it 100% sure that it will be an equal possibility. Also, for each of the 3 possibilities you need to the Control switch set, and also you clear the Control switch so that the next unit on the blue beacon needs to re-randomize the switches before he can teleport as well. Clever, yet simple yes?

To do the simple "re-do" choose one of the four possibilities. I have chosen when the answer is 3, or when S2 = 1 (Set) and S1 = 1 (Set) Examine carefully:

Trigger

Description:

How to "re-do" a 'randomizing'

Players:

¤ Player Kirby

Conditions:

¤ S2 = 1 (Set)

¤ S1 = 1 (Set)

¤ The Control Switch is set.

Actions:

¤ Randomize Switch 2. (Thats the official name when looking at default triggers)

¤ Randomize Switch 1.

¤ Preserve Trigger (In case you need to "re-do" again)

This is a very simple trigger if you can understand it. Because S2 and S1 were not one of the 3 teleporting choices, we just have S2 and S1 "re-do" if you understand what I mean. They each become "null" (neither cleared nor set) and then become either set or cleared. To be truthful, the 'randomization' could make S2 = 1 and S1 = 1 AGAIN instead of becoming one of the three teleporting possibilities. (this is proof of it being almost purely 'random')


Well, there you have it; the extremely long essay-like topic on the detail of how the random triggers work just to teleport from this Blue beacon to either the Teal beacon, the Red beacon, or the Purple beacon.

I sure really do hope this helped you dead marine, I spent 1 hour and 30 minutes writing this in such a way that you could understand it.